// C++ code to linearly search x in arr[].
// If x is present then return its location
// otherwise return -1
#include
using namespace std;
int search(int arr[], int N, int x)
{
int i;
for (i = 0; i < N; i++)
if (arr[i] == x)
return i;
return -1;
}
// Driver's code
int main(void)
{
int arr[] = { 2, 3, 4, 10, 40 };
int x = 10;
int N = sizeof(arr) / sizeof(arr[0]);
// Function call
int result = search(arr, N, x);
(result == -1)
? cout << "Element is not present in array"
: cout << "Element is present at index " << result;
return 0;
}
# Python3 code to linearly search x in arr[].
# If x is present then return its location
# otherwise return -1
def search(arr, N, x):
for i in range(0, N):
if (arr[i] == x):
return i
return -1
# Driver Code
if __name__ == "__main__":
arr = [2, 3, 4, 10, 40]
x = 10
N = len(arr)
# Function call
result = search(arr, N, x)
if(result == -1):
print("Element is not present in array")
else:
print("Element is present at index", result)